3(x+1)12=150+x

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Solution for 3(x+1)12=150+x equation:



3(x+1)12=150+x
We move all terms to the left:
3(x+1)12-(150+x)=0
We add all the numbers together, and all the variables
3(x+1)12-(x+150)=0
We multiply parentheses
36x-(x+150)+36=0
We get rid of parentheses
36x-x-150+36=0
We add all the numbers together, and all the variables
35x-114=0
We move all terms containing x to the left, all other terms to the right
35x=114
x=114/35
x=3+9/35

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