3(x+1)2x=6

Solution for 3(x+1)2x=6 equation:

3(x+1)2x=6

We move all terms to the left:

3(x+1)2x-(6)=0

We multiply parentheses

6x^2+6x-6=0

a = 6; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·6·(-6)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{5}}{2*6}=\frac{-6-6\sqrt{5}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{5}}{2*6}=\frac{-6+6\sqrt{5}}{12}
$