3(x+1)=(21+3x)/2

Solution for 3(x+1)=(21+3x)/2 equation:

3(x+1)=(21+3x)/2

We move all terms to the left:

3(x+1)-((21+3x)/2)=0

We add all the numbers together, and all the variables

3(x+1)-((3x+21)/2)=0

We multiply parentheses

3x-((3x+21)/2)+3=0

We multiply all the terms by the denominator


3x*2)-((3x+21)+3*2)=0

We add all the numbers together, and all the variables

3x*2)-((3x+21)=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$