3(x+1)=(4x-12)+3

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Solution for 3(x+1)=(4x-12)+3 equation:



3(x+1)=(4x-12)+3
We move all terms to the left:
3(x+1)-((4x-12)+3)=0
We multiply parentheses
3x-((4x-12)+3)+3=0
We calculate terms in parentheses: -((4x-12)+3), so:
(4x-12)+3
We get rid of parentheses
4x-12+3
We add all the numbers together, and all the variables
4x-9
Back to the equation:
-(4x-9)
We get rid of parentheses
3x-4x+9+3=0
We add all the numbers together, and all the variables
-1x+12=0
We move all terms containing x to the left, all other terms to the right
-x=-12
x=-12/-1
x=+12

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