3(x+1)=-2(x-1)+16

Solution for 3(x+1)=-2(x-1)+16 equation:

3(x+1)=-2(x-1)+16

We move all terms to the left:

3(x+1)-(-2(x-1)+16)=0

We multiply parentheses

3x-(-2(x-1)+16)+3=0


We calculate terms in parentheses: -(-2(x-1)+16), so:

-2(x-1)+16

We multiply parentheses

-2x+2+16

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)


We get rid of parentheses

3x+2x-18+3=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3