3(x+1)=-2(x-1)/6

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Solution for 3(x+1)=-2(x-1)/6 equation: 



3(x+1)=-2(x-1)/6

We move all terms to the left:

3(x+1)-(-2(x-1)/6)=0

We multiply parentheses

3x-(-2(x-1)/6)+3=0

We multiply all the terms by the denominator


3x*6)-(-2(x-1)+3*6)=0

We add all the numbers together, and all the variables

3x*6)-(-2(x-1)=0

We multiply parentheses

3x*6)-(-2x+2=0

Wy multiply elements

18x^2-2x+2=0

a = 18; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·18·2
Δ = -140
Delta is less than zero, so there is no solution for the equation

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