3(x+1)=-3(5x-2)+6x

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Solution for 3(x+1)=-3(5x-2)+6x equation: 



3(x+1)=-3(5x-2)+6x

We move all terms to the left:

3(x+1)-(-3(5x-2)+6x)=0

We multiply parentheses

3x-(-3(5x-2)+6x)+3=0



We calculate terms in parentheses: -(-3(5x-2)+6x), so:

-3(5x-2)+6x

We add all the numbers together, and all the variables

6x-3(5x-2)

We multiply parentheses

6x-15x+6

We add all the numbers together, and all the variables

-9x+6

Back to the equation:

-(-9x+6)



We get rid of parentheses

3x+9x-6+3=0

We add all the numbers together, and all the variables

12x-3=0

We move all terms containing x to the left, all other terms to the right

12x=3

x=3/12

x=1/4

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