3(x+1)=12+(x-1)

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Solution for 3(x+1)=12+(x-1) equation: 



3(x+1)=12+(x-1)

We move all terms to the left:

3(x+1)-(12+(x-1))=0

We multiply parentheses

3x-(12+(x-1))+3=0



We calculate terms in parentheses: -(12+(x-1)), so:

12+(x-1)

determiningTheFunctionDomain
(x-1)+12

We get rid of parentheses

x-1+12

We add all the numbers together, and all the variables

x+11

Back to the equation:

-(x+11)



We get rid of parentheses

3x-x-11+3=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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