3(x+1)=12+4(x+1)

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Solution for 3(x+1)=12+4(x+1) equation: 



3(x+1)=12+4(x+1)

We move all terms to the left:

3(x+1)-(12+4(x+1))=0

We multiply parentheses

3x-(12+4(x+1))+3=0



We calculate terms in parentheses: -(12+4(x+1)), so:

12+4(x+1)

determiningTheFunctionDomain
4(x+1)+12

We multiply parentheses

4x+4+12

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

3x-4x-16+3=0

We add all the numbers together, and all the variables

-1x-13=0

We move all terms containing x to the left, all other terms to the right

-x=13

x=13/-1

x=-13

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