3(x+1)=2(2x-3)+4

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Solution for 3(x+1)=2(2x-3)+4 equation: 



3(x+1)=2(2x-3)+4

We move all terms to the left:

3(x+1)-(2(2x-3)+4)=0

We multiply parentheses

3x-(2(2x-3)+4)+3=0



We calculate terms in parentheses: -(2(2x-3)+4), so:

2(2x-3)+4

We multiply parentheses

4x-6+4

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

3x-4x+2+3=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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