3(x+1)=2(x+0,5)

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Solution for 3(x+1)=2(x+0,5) equation: 



3(x+1)=2(x+0.5)

We move all terms to the left:

3(x+1)-(2(x+0.5))=0

We multiply parentheses

3x-(2(x+0.5))+3=0



We calculate terms in parentheses: -(2(x+0.5)), so:

2(x+0.5)

We multiply parentheses

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

3x-2x-1+3=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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