3(x+1)=2(x+3)+x-3

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Solution for 3(x+1)=2(x+3)+x-3 equation: 



3(x+1)=2(x+3)+x-3

We move all terms to the left:

3(x+1)-(2(x+3)+x-3)=0

We multiply parentheses

3x-(2(x+3)+x-3)+3=0



We calculate terms in parentheses: -(2(x+3)+x-3), so:

2(x+3)+x-3

We add all the numbers together, and all the variables

x+2(x+3)-3

We multiply parentheses

x+2x+6-3

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

3x-3x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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