3(x+1)=2(x+3)1

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Solution for 3(x+1)=2(x+3)1 equation: 



3(x+1)=2(x+3)1

We move all terms to the left:

3(x+1)-(2(x+3)1)=0

We multiply parentheses

3x-(2(x+3)1)+3=0



We calculate terms in parentheses: -(2(x+3)1), so:

2(x+3)1

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

3x-2x-6+3=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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