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3(x+1)=2x(x+11)
We move all terms to the left:
3(x+1)-(2x(x+11))=0
We multiply parentheses
3x-(2x(x+11))+3=0
We calculate terms in parentheses: -(2x(x+11)), so:We get rid of parentheses
2x(x+11)
We multiply parentheses
2x^2+22x
Back to the equation:
-(2x^2+22x)
-2x^2+3x-22x+3=0
We add all the numbers together, and all the variables
-2x^2-19x+3=0
a = -2; b = -19; c = +3;
Δ = b2-4ac
Δ = -192-4·(-2)·3
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{385}}{2*-2}=\frac{19-\sqrt{385}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{385}}{2*-2}=\frac{19+\sqrt{385}}{-4} $
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