3(x+1)=3(x+3)+x-3

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Solution for 3(x+1)=3(x+3)+x-3 equation: 



3(x+1)=3(x+3)+x-3

We move all terms to the left:

3(x+1)-(3(x+3)+x-3)=0

We multiply parentheses

3x-(3(x+3)+x-3)+3=0



We calculate terms in parentheses: -(3(x+3)+x-3), so:

3(x+3)+x-3

We add all the numbers together, and all the variables

x+3(x+3)-3

We multiply parentheses

x+3x+9-3

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

3x-4x-6+3=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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