3(x+1)=4x+12

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Solution for 3(x+1)=4x+12 equation: 



3(x+1)=4x+12

We move all terms to the left:

3(x+1)-(4x+12)=0

We multiply parentheses

3x-(4x+12)+3=0

We get rid of parentheses

3x-4x-12+3=0

We add all the numbers together, and all the variables

-1x-9=0

We move all terms containing x to the left, all other terms to the right

-x=9

x=9/-1

x=-9

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