3(x+1)=6(1-x)+6

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Solution for 3(x+1)=6(1-x)+6 equation: 



3(x+1)=6(1-x)+6

We move all terms to the left:

3(x+1)-(6(1-x)+6)=0

We add all the numbers together, and all the variables

3(x+1)-(6(-1x+1)+6)=0

We multiply parentheses

3x-(6(-1x+1)+6)+3=0



We calculate terms in parentheses: -(6(-1x+1)+6), so:

6(-1x+1)+6

We multiply parentheses

-6x+6+6

We add all the numbers together, and all the variables

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

3x+6x-12+3=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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