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3(x+1)=6(5x-1)
We move all terms to the left:
3(x+1)-(6(5x-1))=0
We multiply parentheses
3x-(6(5x-1))+3=0
We calculate terms in parentheses: -(6(5x-1)), so:We get rid of parentheses
6(5x-1)
We multiply parentheses
30x-6
Back to the equation:
-(30x-6)
3x-30x+6+3=0
We add all the numbers together, and all the variables
-27x+9=0
We move all terms containing x to the left, all other terms to the right
-27x=-9
x=-9/-27
x=1/3
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