3(x+1)=7(x-2)=-3

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Solution for 3(x+1)=7(x-2)=-3 equation: 



3(x+1)=7(x-2)=-3

We move all terms to the left:

3(x+1)-(7(x-2))=0

We multiply parentheses

3x-(7(x-2))+3=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

3x-7x+14+3=0

We add all the numbers together, and all the variables

-4x+17=0

We move all terms containing x to the left, all other terms to the right

-4x=-17

x=-17/-4

x=4+1/4

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