3(x+1)=8(x-1)-4

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Solution for 3(x+1)=8(x-1)-4 equation:


Simplifying
3(x + 1) = 8(x + -1) + -4

Reorder the terms:
3(1 + x) = 8(x + -1) + -4
(1 * 3 + x * 3) = 8(x + -1) + -4
(3 + 3x) = 8(x + -1) + -4

Reorder the terms:
3 + 3x = 8(-1 + x) + -4
3 + 3x = (-1 * 8 + x * 8) + -4
3 + 3x = (-8 + 8x) + -4

Reorder the terms:
3 + 3x = -8 + -4 + 8x

Combine like terms: -8 + -4 = -12
3 + 3x = -12 + 8x

Solving
3 + 3x = -12 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
3 + 3x + -8x = -12 + 8x + -8x

Combine like terms: 3x + -8x = -5x
3 + -5x = -12 + 8x + -8x

Combine like terms: 8x + -8x = 0
3 + -5x = -12 + 0
3 + -5x = -12

Add '-3' to each side of the equation.
3 + -3 + -5x = -12 + -3

Combine like terms: 3 + -3 = 0
0 + -5x = -12 + -3
-5x = -12 + -3

Combine like terms: -12 + -3 = -15
-5x = -15

Divide each side by '-5'.
x = 3

Simplifying
x = 3

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