3(x+1)=x+33

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Solution for 3(x+1)=x+33 equation: 



3(x+1)=x+33

We move all terms to the left:

3(x+1)-(x+33)=0

We multiply parentheses

3x-(x+33)+3=0

We get rid of parentheses

3x-x-33+3=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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