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3(x+10)=2(x+20)
We move all terms to the left:
3(x+10)-(2(x+20))=0
We multiply parentheses
3x-(2(x+20))+30=0
We calculate terms in parentheses: -(2(x+20)), so:We get rid of parentheses
2(x+20)
We multiply parentheses
2x+40
Back to the equation:
-(2x+40)
3x-2x-40+30=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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