3(x+12)+x=3(4x-3)+1

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Solution for 3(x+12)+x=3(4x-3)+1 equation: 



3(x+12)+x=3(4x-3)+1

We move all terms to the left:

3(x+12)+x-(3(4x-3)+1)=0

We add all the numbers together, and all the variables

x+3(x+12)-(3(4x-3)+1)=0

We multiply parentheses

x+3x-(3(4x-3)+1)+36=0



We calculate terms in parentheses: -(3(4x-3)+1), so:

3(4x-3)+1

We multiply parentheses

12x-9+1

We add all the numbers together, and all the variables

12x-8

Back to the equation:

-(12x-8)



We add all the numbers together, and all the variables

4x-(12x-8)+36=0

We get rid of parentheses

4x-12x+8+36=0

We add all the numbers together, and all the variables

-8x+44=0

We move all terms containing x to the left, all other terms to the right

-8x=-44

x=-44/-8

x=5+1/2

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