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3(x+12)/5(x+2)=12
We move all terms to the left:
3(x+12)/5(x+2)-(12)=0
Domain of the equation: 5(x+2)!=0We multiply all the terms by the denominator
x∈R
3(x+12)-12*5(x+2)=0
We multiply parentheses
3x-12*5(x+2)+36=0
Wy multiply elements
3x-60x(x+36=0
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