3(x+12)=-2(x-4)+x

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Solution for 3(x+12)=-2(x-4)+x equation: 



3(x+12)=-2(x-4)+x

We move all terms to the left:

3(x+12)-(-2(x-4)+x)=0

We multiply parentheses

3x-(-2(x-4)+x)+36=0



We calculate terms in parentheses: -(-2(x-4)+x), so:

-2(x-4)+x

We add all the numbers together, and all the variables

x-2(x-4)

We multiply parentheses

x-2x+8

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We get rid of parentheses

3x+1x-8+36=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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