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3(x+12)=2(x+5)
We move all terms to the left:
3(x+12)-(2(x+5))=0
We multiply parentheses
3x-(2(x+5))+36=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
3x-2x-10+36=0
We add all the numbers together, and all the variables
x+26=0
We move all terms containing x to the left, all other terms to the right
x=-26
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