3(x+12)=4(x-5)

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Solution for 3(x+12)=4(x-5) equation: 



3(x+12)=4(x-5)

We move all terms to the left:

3(x+12)-(4(x-5))=0

We multiply parentheses

3x-(4(x-5))+36=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

3x-4x+20+36=0

We add all the numbers together, and all the variables

-1x+56=0

We move all terms containing x to the left, all other terms to the right

-x=-56

x=-56/-1

x=+56

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