3(x+12)=7x-6(2x+7)

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Solution for 3(x+12)=7x-6(2x+7) equation: 



3(x+12)=7x-6(2x+7)

We move all terms to the left:

3(x+12)-(7x-6(2x+7))=0

We multiply parentheses

3x-(7x-6(2x+7))+36=0



We calculate terms in parentheses: -(7x-6(2x+7)), so:

7x-6(2x+7)

We multiply parentheses

7x-12x-42

We add all the numbers together, and all the variables

-5x-42

Back to the equation:

-(-5x-42)



We get rid of parentheses

3x+5x+42+36=0

We add all the numbers together, and all the variables

8x+78=0

We move all terms containing x to the left, all other terms to the right

8x=-78

x=-78/8

x=-9+3/4

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