3(x+19)+2x-10=100

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Solution for 3(x+19)+2x-10=100 equation: 



3(x+19)+2x-10=100

We move all terms to the left:

3(x+19)+2x-10-(100)=0

We add all the numbers together, and all the variables

2x+3(x+19)-110=0

We multiply parentheses

2x+3x+57-110=0

We add all the numbers together, and all the variables

5x-53=0

We move all terms containing x to the left, all other terms to the right

5x=53

x=53/5

x=10+3/5

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