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3(x+2)(5x+9)=0
We multiply parentheses ..
3(+5x^2+9x+10x+18)=0
We multiply parentheses
15x^2+27x+30x+54=0
We add all the numbers together, and all the variables
15x^2+57x+54=0
a = 15; b = 57; c = +54;
Δ = b2-4ac
Δ = 572-4·15·54
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-3}{2*15}=\frac{-60}{30} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+3}{2*15}=\frac{-54}{30} =-1+4/5 $
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