3(x+2)+(x-4)=28

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Solution for 3(x+2)+(x-4)=28 equation: 



3(x+2)+(x-4)=28

We move all terms to the left:

3(x+2)+(x-4)-(28)=0

We multiply parentheses

3x+(x-4)+6-28=0

We get rid of parentheses

3x+x-4+6-28=0

We add all the numbers together, and all the variables

4x-26=0

We move all terms containing x to the left, all other terms to the right

4x=26

x=26/4

x=6+1/2

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