3(x+2)+(x-4)=x-3(x+3

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Solution for 3(x+2)+(x-4)=x-3(x+3 equation: 



3(x+2)+(x-4)=x-3(x+3

We move all terms to the left:

3(x+2)+(x-4)-(x-3(x+3)=0

We multiply parentheses

3x+(x-4)-(x-3(x+3)+6=0

We get rid of parentheses

3x+x-(x-3(x+3)+6-4=0

We add all the numbers together, and all the variables

4x-(x-3(x+3)+6-4=0

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