3(x+2)+0.5x=41

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Solution for 3(x+2)+0.5x=41 equation: 



3(x+2)+0.5x=41

We move all terms to the left:

3(x+2)+0.5x-(41)=0

We add all the numbers together, and all the variables

0.5x+3(x+2)-41=0

We multiply parentheses

0.5x+3x+6-41=0

We add all the numbers together, and all the variables

3.5x-35=0

We move all terms containing x to the left, all other terms to the right

3.5x=35

x=35/3.5

x=10

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