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3(x+2)+1+2x=2(2x+2)+x
We move all terms to the left:
3(x+2)+1+2x-(2(2x+2)+x)=0
We add all the numbers together, and all the variables
2x+3(x+2)-(2(2x+2)+x)+1=0
We multiply parentheses
2x+3x-(2(2x+2)+x)+6+1=0
We calculate terms in parentheses: -(2(2x+2)+x), so:We add all the numbers together, and all the variables
2(2x+2)+x
We add all the numbers together, and all the variables
x+2(2x+2)
We multiply parentheses
x+4x+4
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
5x-(5x+4)+7=0
We get rid of parentheses
5x-5x-4+7=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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