3(x+2)+12=2(x+4)-5

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Solution for 3(x+2)+12=2(x+4)-5 equation: 



3(x+2)+12=2(x+4)-5

We move all terms to the left:

3(x+2)+12-(2(x+4)-5)=0

We multiply parentheses

3x-(2(x+4)-5)+6+12=0



We calculate terms in parentheses: -(2(x+4)-5), so:

2(x+4)-5

We multiply parentheses

2x+8-5

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

3x-(2x+3)+18=0

We get rid of parentheses

3x-2x-3+18=0

We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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