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3(x+2)+1=5x-2(-3+x)
We move all terms to the left:
3(x+2)+1-(5x-2(-3+x))=0
We add all the numbers together, and all the variables
3(x+2)-(5x-2(x-3))+1=0
We multiply parentheses
3x-(5x-2(x-3))+6+1=0
We calculate terms in parentheses: -(5x-2(x-3)), so:We add all the numbers together, and all the variables
5x-2(x-3)
We multiply parentheses
5x-2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
3x-(3x+6)+7=0
We get rid of parentheses
3x-3x-6+7=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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