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3(x+2)+2(2x+1)=15*
We move all terms to the left:
3(x+2)+2(2x+1)-(15*)=0
We add all the numbers together, and all the variables
3(x+2)+2(2x+1)-0=0
We add all the numbers together, and all the variables
3(x+2)+2(2x+1)=0
We multiply parentheses
3x+4x+6+2=0
We add all the numbers together, and all the variables
7x+8=0
We move all terms containing x to the left, all other terms to the right
7x=-8
x=-8/7
x=-1+1/7
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