3(x+2)+3(2x-1)=5(x-2)

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Solution for 3(x+2)+3(2x-1)=5(x-2) equation: 



3(x+2)+3(2x-1)=5(x-2)

We move all terms to the left:

3(x+2)+3(2x-1)-(5(x-2))=0

We multiply parentheses

3x+6x-(5(x-2))+6-3=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

9x-(5x-10)+3=0

We get rid of parentheses

9x-5x+10+3=0

We add all the numbers together, and all the variables

4x+13=0

We move all terms containing x to the left, all other terms to the right

4x=-13

x=-13/4

x=-3+1/4

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