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3(x+2)+3=6x-3(-2+x)
We move all terms to the left:
3(x+2)+3-(6x-3(-2+x))=0
We add all the numbers together, and all the variables
3(x+2)-(6x-3(x-2))+3=0
We multiply parentheses
3x-(6x-3(x-2))+6+3=0
We calculate terms in parentheses: -(6x-3(x-2)), so:We add all the numbers together, and all the variables
6x-3(x-2)
We multiply parentheses
6x-3x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
3x-(3x+6)+9=0
We get rid of parentheses
3x-3x-6+9=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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