3(x+2)+4(2x+1)=1x-2(x+6)

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Solution for 3(x+2)+4(2x+1)=1x-2(x+6) equation: 



3(x+2)+4(2x+1)=1x-2(x+6)

We move all terms to the left:

3(x+2)+4(2x+1)-(1x-2(x+6))=0

We multiply parentheses

3x+8x-(1x-2(x+6))+6+4=0



We calculate terms in parentheses: -(1x-2(x+6)), so:

1x-2(x+6)

We add all the numbers together, and all the variables

x-2(x+6)

We multiply parentheses

x-2x-12

We add all the numbers together, and all the variables

-1x-12

Back to the equation:

-(-1x-12)



We add all the numbers together, and all the variables

11x-(-1x-12)+10=0

We get rid of parentheses

11x+1x+12+10=0

We add all the numbers together, and all the variables

12x+22=0

We move all terms containing x to the left, all other terms to the right

12x=-22

x=-22/12

x=-1+5/6

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