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3(x+2)+4(2x+1)=5(x-2)
We move all terms to the left:
3(x+2)+4(2x+1)-(5(x-2))=0
We multiply parentheses
3x+8x-(5(x-2))+6+4=0
We calculate terms in parentheses: -(5(x-2)), so:We add all the numbers together, and all the variables
5(x-2)
We multiply parentheses
5x-10
Back to the equation:
-(5x-10)
11x-(5x-10)+10=0
We get rid of parentheses
11x-5x+10+10=0
We add all the numbers together, and all the variables
6x+20=0
We move all terms containing x to the left, all other terms to the right
6x=-20
x=-20/6
x=-3+1/3
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