3(x+2)+4(2x+1)=6x=20

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Solution for 3(x+2)+4(2x+1)=6x=20 equation: 



3(x+2)+4(2x+1)=6x=20

We move all terms to the left:

3(x+2)+4(2x+1)-(6x)=0

We add all the numbers together, and all the variables

-6x+3(x+2)+4(2x+1)=0

We multiply parentheses

-6x+3x+8x+6+4=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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