3(x+2)+4(2x-6)=6(x-4)+8(2x+1)

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Solution for 3(x+2)+4(2x-6)=6(x-4)+8(2x+1) equation: 



3(x+2)+4(2x-6)=6(x-4)+8(2x+1)

We move all terms to the left:

3(x+2)+4(2x-6)-(6(x-4)+8(2x+1))=0

We multiply parentheses

3x+8x-(6(x-4)+8(2x+1))+6-24=0



We calculate terms in parentheses: -(6(x-4)+8(2x+1)), so:

6(x-4)+8(2x+1)

We multiply parentheses

6x+16x-24+8

We add all the numbers together, and all the variables

22x-16

Back to the equation:

-(22x-16)



We add all the numbers together, and all the variables

11x-(22x-16)-18=0

We get rid of parentheses

11x-22x+16-18=0

We add all the numbers together, and all the variables

-11x-2=0

We move all terms containing x to the left, all other terms to the right

-11x=2

x=2/-11

x=-2/11

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