3(x+2)+4(x+1)=73

Solution for 3(x+2)+4(x+1)=73 equation:

Simplifying
3(x + 2) + 4(x + 1) = 73

Reorder the terms:
3(2 + x) + 4(x + 1) = 73
(2 * 3 + x * 3) + 4(x + 1) = 73
(6 + 3x) + 4(x + 1) = 73

Reorder the terms:
6 + 3x + 4(1 + x) = 73
6 + 3x + (1 * 4 + x * 4) = 73
6 + 3x + (4 + 4x) = 73

Reorder the terms:
6 + 4 + 3x + 4x = 73

Combine like terms: 6 + 4 = 10
10 + 3x + 4x = 73

Combine like terms: 3x + 4x = 7x
10 + 7x = 73

Solving
10 + 7x = 73

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 7x = 73 + -10

Combine like terms: 10 + -10 = 0
0 + 7x = 73 + -10
7x = 73 + -10

Combine like terms: 73 + -10 = 63
7x = 63

Divide each side by '7'.
x = 9

Simplifying
x = 9