3(x+2)+4(x+7)=5(x-2)+6(x-1)

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Solution for 3(x+2)+4(x+7)=5(x-2)+6(x-1) equation: 



3(x+2)+4(x+7)=5(x-2)+6(x-1)

We move all terms to the left:

3(x+2)+4(x+7)-(5(x-2)+6(x-1))=0

We multiply parentheses

3x+4x-(5(x-2)+6(x-1))+6+28=0



We calculate terms in parentheses: -(5(x-2)+6(x-1)), so:

5(x-2)+6(x-1)

We multiply parentheses

5x+6x-10-6

We add all the numbers together, and all the variables

11x-16

Back to the equation:

-(11x-16)



We add all the numbers together, and all the variables

7x-(11x-16)+34=0

We get rid of parentheses

7x-11x+16+34=0

We add all the numbers together, and all the variables

-4x+50=0

We move all terms containing x to the left, all other terms to the right

-4x=-50

x=-50/-4

x=12+1/2

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