3(x+2)+4=4(x+3)+3

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Solution for 3(x+2)+4=4(x+3)+3 equation: 



3(x+2)+4=4(x+3)+3

We move all terms to the left:

3(x+2)+4-(4(x+3)+3)=0

We multiply parentheses

3x-(4(x+3)+3)+6+4=0



We calculate terms in parentheses: -(4(x+3)+3), so:

4(x+3)+3

We multiply parentheses

4x+12+3

We add all the numbers together, and all the variables

4x+15

Back to the equation:

-(4x+15)



We add all the numbers together, and all the variables

3x-(4x+15)+10=0

We get rid of parentheses

3x-4x-15+10=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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