3(x+2)+4x-5=-(x+1)-6

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Solution for 3(x+2)+4x-5=-(x+1)-6 equation:



3(x+2)+4x-5=-(x+1)-6
We move all terms to the left:
3(x+2)+4x-5-(-(x+1)-6)=0
We add all the numbers together, and all the variables
4x+3(x+2)-(-(x+1)-6)-5=0
We multiply parentheses
4x+3x-(-(x+1)-6)+6-5=0
We calculate terms in parentheses: -(-(x+1)-6), so:
-(x+1)-6
We get rid of parentheses
-x-1-6
We add all the numbers together, and all the variables
-1x-7
Back to the equation:
-(-1x-7)
We add all the numbers together, and all the variables
7x-(-1x-7)+1=0
We get rid of parentheses
7x+1x+7+1=0
We add all the numbers together, and all the variables
8x+8=0
We move all terms containing x to the left, all other terms to the right
8x=-8
x=-8/8
x=-1

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