3(x+2)+4x-5=7(x+1

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Solution for 3(x+2)+4x-5=7(x+1 equation: 



3(x+2)+4x-5=7(x+1

We move all terms to the left:

3(x+2)+4x-5-(7(x+1)=0

We add all the numbers together, and all the variables

4x+3(x+2)-(7(x+1)-5=0

We multiply parentheses

4x+3x-(7(x+1)-5+6=0

We add all the numbers together, and all the variables

7x-(7(x+1)-5+6=0

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