3(x+2)+4x-5=7(x+1)

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Solution for 3(x+2)+4x-5=7(x+1) equation: 


Simplifying
3(x + 2) + 4x + -5 = 7(x + 1)

Reorder the terms:
3(2 + x) + 4x + -5 = 7(x + 1)
(2 * 3 + x * 3) + 4x + -5 = 7(x + 1)
(6 + 3x) + 4x + -5 = 7(x + 1)

Reorder the terms:
6 + -5 + 3x + 4x = 7(x + 1)

Combine like terms: 6 + -5 = 1
1 + 3x + 4x = 7(x + 1)

Combine like terms: 3x + 4x = 7x
1 + 7x = 7(x + 1)

Reorder the terms:
1 + 7x = 7(1 + x)
1 + 7x = (1 * 7 + x * 7)
1 + 7x = (7 + 7x)

Add '-7x' to each side of the equation.
1 + 7x + -7x = 7 + 7x + -7x

Combine like terms: 7x + -7x = 0
1 + 0 = 7 + 7x + -7x
1 = 7 + 7x + -7x

Combine like terms: 7x + -7x = 0
1 = 7 + 0
1 = 7

Solving
1 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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