3(x+2)+4x-5=7-(x+1)-6

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Solution for 3(x+2)+4x-5=7-(x+1)-6 equation: 



3(x+2)+4x-5=7-(x+1)-6

We move all terms to the left:

3(x+2)+4x-5-(7-(x+1)-6)=0

We add all the numbers together, and all the variables

4x+3(x+2)-(7-(x+1)-6)-5=0

We multiply parentheses

4x+3x-(7-(x+1)-6)+6-5=0



We calculate terms in parentheses: -(7-(x+1)-6), so:

7-(x+1)-6

determiningTheFunctionDomain
-(x+1)+7-6

We add all the numbers together, and all the variables

-(x+1)+1

We get rid of parentheses

-x-1+1

We add all the numbers together, and all the variables

-x

Back to the equation:

-(-x)



We add all the numbers together, and all the variables

4x+3x-(-1x)+6-5=0

We add all the numbers together, and all the variables

7x-(-1x)+1=0

We get rid of parentheses

7x+1x+1=0

We add all the numbers together, and all the variables

8x+1=0

We move all terms containing x to the left, all other terms to the right

8x=-1

x=-1/8

x=-1/8

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